Hi,

i have a network with 3 bore hole pumps that connect to a main manifold and from that manifold one pipe fill a tank.

can epanet simulate such a network?

thanks,

Ari.

# Can EPANET calculate a network with multiple pumps?

Its possible, I try to model a system having 12 boreholes and successfully run ,

Just assign neg demand at each node which represents a boreholes. Then run

how to model booster pump?

If you want to model the borehole pump,

you can model each borehole as a sequence of reservoir and pump

The reservoir head will represent the water level in the aquifer

The pump is characterized by a pump curve

thanks gal.

I’m actually know how to model a single borehole pump (I’m doing it exactly as you wrote).

the question is can epanet simulate multiple pumps (pump’s curve, it doesn’t necessarily need to be a bore hole pumps) that feed one manifold.

I’ve attached a simple drawing to show what i mean.

thanks,

Ari.

no.

those pumps are individual and connect parallelly, not in a row.

those pumps connect to a collecting manifold, and from that one a single pipe fill a reservoir.

@aridzv Have a look at this network here with three pumps in parallel:

https://emps.exeter.ac.uk/engineering/research/cws/resources/benchmarks/expansion/d-town.php

The INP file is here:

https://emps.exeter.ac.uk/media/universityofexeter/emps/research/cws/downloads/d-town.inp

thanks elad.

i have 2 more quotations, if I may:

- i didn’t see any P.S.V’s after the pumps. how do this model set/fix the pump’s flow?
- can i use Cramer’s rule to develop the head-flow equation from a given pump graph?

thanks,

Ari.

@aridzv, regarding your questions:

- The pump flow is determined by the intersection of the pump curve and the system (resistance) curve. If you aim to set a constant flow you might consider using a variable speed pump.
- I am not familiar with Cramer’s rule in the context of pump curves. EPANET allows you to insert the curve as a set of discrete points and then it will build the continuous graph on its own

Gal